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<blockquote data-quote="Andy Ful" data-source="post: 1022756" data-attributes="member: 32260"><p>The previous post revealed some interesting possibilities. So, now I will apply the calculator to the two-year statistics from the OP. The table will use blocked samples instead of missed samples.</p><p></p><p><strong>Real-World Triathlon 2021-2022: SE Labs, AV-Comparatives, AV-Test (7548 samples in 24 tests)</strong></p><p></p><p>------------------ Blocked samples</p><p><strong><span style="color: rgb(0, 168, 133)">Norton 360...................7536</span></strong></p><p><strong><span style="color: rgb(0, 168, 133)">Avast............................7535</span></strong></p><p><strong><span style="color: rgb(0, 168, 133)">Kaspersky....................7530</span></strong></p><p><strong><span style="color: rgb(41, 105, 176)">Microsoft.....................7520.5</span></strong></p><p><span style="color: rgb(41, 105, 176)"><strong>McAfee ........................7511</strong></span></p><p><span style="color: rgb(41, 105, 176)"><strong>Avira ............................7505</strong></span></p><p></p><p></p><p>Norton is better than Microsoft if:</p><p>"Norton 360" - error ~ Microsoft + error ----> error = 7.75 samples</p><p>Margin of error = 7.75/7536 *100% = 0.103%</p><p>Population Proportion = 7536/7548 *100% = 99.841%</p><p>[ATTACH=full]272598[/ATTACH]</p><p></p><p>On the basis of the above the sests from 1 and half year (AV-Comparatives+AV-Test+SE Labs) would be sufficient to prove (with confidence Level 95%) that Norton can provide better protection than Microsoft.</p><p></p><p>Analogical calculations for Kaspersky and Microsoft :</p><p>Margin of error = 4.75/7530 *100% = 0.0631%</p><p>Population Proportion = 7530/7548 *100% = 99.761%</p><p>[ATTACH=full]272601[/ATTACH]</p><p>If the statistical model of this calculator is true, then the sample size 7834 would require about 2 years of testing (AV-Comparatives + AV-Test + SE Labs). But, in the case of Kaspersky, the Confidence Level will be much lower (75%).</p></blockquote><p></p>
[QUOTE="Andy Ful, post: 1022756, member: 32260"] The previous post revealed some interesting possibilities. So, now I will apply the calculator to the two-year statistics from the OP. The table will use blocked samples instead of missed samples. [B]Real-World Triathlon 2021-2022: SE Labs, AV-Comparatives, AV-Test (7548 samples in 24 tests)[/B] ------------------ Blocked samples [B][COLOR=rgb(0, 168, 133)]Norton 360...................7536 Avast............................7535 Kaspersky....................7530[/COLOR] [COLOR=rgb(41, 105, 176)]Microsoft.....................7520.5[/COLOR][/B] [COLOR=rgb(41, 105, 176)][B]McAfee ........................7511 Avira ............................7505[/B][/COLOR] Norton is better than Microsoft if: "Norton 360" - error ~ Microsoft + error ----> error = 7.75 samples Margin of error = 7.75/7536 *100% = 0.103% Population Proportion = 7536/7548 *100% = 99.841% [ATTACH type="full" alt="1675274508677.png"]272598[/ATTACH] On the basis of the above the sests from 1 and half year (AV-Comparatives+AV-Test+SE Labs) would be sufficient to prove (with confidence Level 95%) that Norton can provide better protection than Microsoft. Analogical calculations for Kaspersky and Microsoft : Margin of error = 4.75/7530 *100% = 0.0631% Population Proportion = 7530/7548 *100% = 99.761% [ATTACH type="full" alt="1675276092717.png"]272601[/ATTACH] If the statistical model of this calculator is true, then the sample size 7834 would require about 2 years of testing (AV-Comparatives + AV-Test + SE Labs). But, in the case of Kaspersky, the Confidence Level will be much lower (75%). [/QUOTE]
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